Counter Intuitive I

West plays in 6 against North's lead of the 10.

Declarer cashes three top hearts and two top diamonds.  South discards on the third heart and also on the second diamond.  Declarer now claims twelve tricks.  How?

This is another great candidate for misdirection of the solver, who might fruitlessly attempt to create some sort of squeeze position.

Declarer cashes the A and the other two top diamonds, discarding clubs.  If north shows out on the first club, he is immediately squeezed in three suits.  If north follows to the club lead, then declarer plays three rounds of spades.  If north follows to three spades, then he must be 3-4-5-1; the spade jack is overtaken, and dummy's fourth spade is cashed.

If north shows out on the second or third spade, any discards must be in clubs, lest he set up a red-suit winner.  Unless south unguarded spades along the way, the spade jack wins; then, south is thrown in with a club to lead a spade to dummy at the end.